What is the integral from-1 to 2 of 3x ?

The integral from-1 to 2 of 3x is 9/2

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integral from-1 to 2 of 3x

\int_{- 1}^{2} 3 x d x

\frac{9}{2}

Decimal Notation

4.5

Solution steps

\int_{- 1}^{2} 3 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{- 1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{- 1}^{2}

= 3 [\frac{x ^{2}}{2}]_{- 1}^{2}

Compute the boundaries:

\frac{3}{2}

= 3 \cdot \frac{3}{2}

Simplify

= \frac{9}{2}

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