What is the integral from 0 to 1 of 3y ?

The integral from 0 to 1 of 3y is 3/2

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integral from 0 to 1 of 3y

\int_{0}^{1} 3 y d y

\frac{3}{2}

Decimal Notation

1.5

Solution steps

\int_{0}^{1} 3 y d y

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{1} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{1}

= 3 [\frac{y ^{2}}{2}]_{0}^{1}

Compute the boundaries:

\frac{1}{2}

= 3 \cdot \frac{1}{2}

Simplify

= \frac{3}{2}

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