What is the integral from 0 to 1 of e^y ?

The integral from 0 to 1 of e^y is e-1

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integral from 0 to 1 of e^y

\int_{0}^{1} e^{y} d y

e - 1

Decimal Notation

1.71828 \dots

Solution steps

\int_{0}^{1} e^{y} d y

Use the common integral:

\int e^{y} d y = e^{y}

= [e^{y}]_{0}^{1}

Compute the boundaries:

e - 1

= e - 1

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\int_{0}^{\frac{π}{3}} 9 sec^{2} (x) d x

\int_{0}^{1} x^{2} x^{3} + 1 d x

\int_{0}^{9} \frac{1}{x ^{2} + 81} d x

What is the integral from 0 to 1 of e^y ?
The integral from 0 to 1 of e^y is e-1