What is the integral from-1 to 0 of 2e^x ?

The integral from-1 to 0 of 2e^x is 2(1-1/e)

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integral from-1 to 0 of 2e^x

\int_{- 1}^{0} 2 e^{x} d x

2 (1 - \frac{1}{e})

Decimal

1.26424 \dots

Solution steps

\int_{- 1}^{0} 2 e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{- 1}^{0} e^{x} d x

Use the common integral:

\int e^{x} d x = e^{x}

= 2 [e^{x}]_{- 1}^{0}

Compute the boundaries:

1 - \frac{1}{e}

= 2 (1 - \frac{1}{e})

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What is the integral from-1 to 0 of 2e^x ?
The integral from-1 to 0 of 2e^x is 2(1-1/e)