What is the integral from 8 to 17 of xsqrt(x^2-64) ?

The integral from 8 to 17 of xsqrt(x^2-64) is 1125

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integral from 8 to 17 of xsqrt(x^2-64)

\int_{8}^{17} x x^{2} - 64 d x

1125

Solution steps

\int_{8}^{17} x x^{2} - 64 d x

Apply u-substitution

: \int_{0}^{15} u^{2} d u

= \int_{0}^{15} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{0}^{15}

= [\frac{u ^{3}}{3}]_{0}^{15}

Compute the boundaries:

1125

= 1125

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What is the integral from 8 to 17 of xsqrt(x^2-64) ?
The integral from 8 to 17 of xsqrt(x^2-64) is 1125