What is the integral from y to infinity of e^{-x} ?

The integral from y to infinity of e^{-x} is e^{-y}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from y to infinity of e^{-x}

\int_{y}^{\infty} e^{- x} d x

e^{- y}

Solution steps

\int_{y}^{\infty} e^{- x} d x

Compute the indefinite integral:

\int e^{- x} d x = - e^{- x} + C

Compute the boundaries:

\int_{y}^{\infty} e^{- x} d x = 0 - (- e^{- y})

= 0 - (- e^{- y})

Simplify

= e^{- y}

\int_{0}^{x} y d y

\int_{y}^{1} y ln (x) d x

\int_{0}^{2} \frac{1}{x ^{2} + 1} d x

\int_{0}^{1} (3 + x^{2})^{2} x d x

\int_{- 1}^{2} (4 x - 6 x^{2}) d x

What is the integral from y to infinity of e^{-x} ?
The integral from y to infinity of e^{-x} is e^{-y}