What is the integral from 0 to 2 of 1/(x^2+1) ?

The integral from 0 to 2 of 1/(x^2+1) is arctan(2)

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integral from 0 to 2 of 1/(x^2+1)

\int_{0}^{2} \frac{1}{x ^{2} + 1} d x

arctan (2)

Decimal

1.10714 \dots

Solution steps

\int_{0}^{2} \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = arctan (x)

= [arctan (x)]_{0}^{2}

Compute the boundaries:

arctan (2)

= arctan (2)

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What is the integral from 0 to 2 of 1/(x^2+1) ?
The integral from 0 to 2 of 1/(x^2+1) is arctan(2)