What is the integral from 1 to 2 of 1/(t^2) ?

The integral from 1 to 2 of 1/(t^2) is 1/2

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integral from 1 to 2 of 1/(t^2)

\int_{1}^{2} \frac{1}{t ^{2}} d t

\frac{1}{2}

Solution steps

\int_{1}^{2} \frac{1}{t ^{2}} d t

Apply the Power Rule

: [- \frac{1}{t}]_{1}^{2}

= [- \frac{1}{t}]_{1}^{2}

Compute the boundaries:

\frac{1}{2}

= \frac{1}{2}

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What is the integral from 1 to 2 of 1/(t^2) ?
The integral from 1 to 2 of 1/(t^2) is 1/2