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Popular >

integral from-1 to 1 of |x^2-x|

Solution

\int_{- 1}^{1} x^{2} - x d x

Solution

1

Solution steps

\int_{- 1}^{1} x^{2} - x d x

Eliminate Absolutes

= \int_{- 1}^{0} x^{2} - x d x + \int_{0}^{1} - x^{2} + x d x

\int_{- 1}^{0} x^{2} - x d x = \frac{5}{6}

\int_{0}^{1} - x^{2} + x d x = \frac{1}{6}

= \frac{5}{6} + \frac{1}{6}

Simplify

\frac{5}{6} + \frac{1}{6} : 1

= 1

Popular Examples

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\int_{1}^{2} \frac{1}{x + 1} d x

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\int_{0}^{1} \frac{e ^{z} + 7}{e ^{z} + 7 z} d z

integral from 0 to 2 of 1/(sqrt(2x-x^2))

\int_{0}^{2} \frac{1}{2 x - x ^{2}} d x

integral from 0 to 2 of pix

\int_{0}^{2} π x d x

integral from-4 to 4 of (4-|x|)

\int_{- 4}^{4} (4 - ∣ x ∣) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of |x^2-x| ?
The integral from-1 to 1 of |x^2-x| is 1