What is the integral from 2 to 8 of 1/(x^2) ?

The integral from 2 to 8 of 1/(x^2) is 3/8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 2 to 8 of 1/(x^2)

\int_{2}^{8} \frac{1}{x ^{2}} d x

\frac{3}{8}

Decimal Notation

0.375

Solution steps

\int_{2}^{8} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{8}

= [- \frac{1}{x}]_{2}^{8}

Compute the boundaries:

\frac{3}{8}

= \frac{3}{8}

\int_{- \infty}^{0} 4 - x d x

\int_{0}^{1} e^{x} (x^{2} + x) d x

\int_{\frac{π}{4}}^{\frac{π}{2}} csc^{2} (x) d x

\int_{1}^{3} \frac{8 ( ln ( x ) ) ^{3}}{x} d x

\int_{- 3}^{- 1} (x^{2} + x + 6) d x

What is the integral from 2 to 8 of 1/(x^2) ?
The integral from 2 to 8 of 1/(x^2) is 3/8