What is the integral from-2 to 3 of 3/(2x^2) ?

The integral from-2 to 3 of 3/(2x^2) is diverges

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integral from-2 to 3 of 3/(2x^2)

\int_{- 2}^{3} \frac{3}{2 x ^{2}} d x

diverges

Solution steps

\int_{- 2}^{3} \frac{3}{2 x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 2}^{0} \frac{3}{2 x ^{2}} d x + \int_{0}^{3} \frac{3}{2 x ^{2}} d x

\int_{- 2}^{0} \frac{3}{2 x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{1} y^{2} 4 y^{2} + 1 d y

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\int_{0}^{\frac{π}{6}} tan^{3} (2 x) d x

\int_{0}^{x^{2}} \frac{1}{1 + t} d t

\int_{0}^{a} \frac{1}{a ^{2} + x ^{2}} d x

What is the integral from-2 to 3 of 3/(2x^2) ?
The integral from-2 to 3 of 3/(2x^2) is diverges