What is the integral from 0 to a of 1/(a^2+x^2) ?

The integral from 0 to a of 1/(a^2+x^2) is pi/(4a)

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integral from 0 to a of 1/(a^2+x^2)

\int_{0}^{a} \frac{1}{a ^{2} + x ^{2}} d x

\frac{π}{4 a}

Solution steps

\int_{0}^{a} \frac{1}{a ^{2} + x ^{2}} d x

Apply Integral Substitution

= \int_{0}^{1} \frac{1}{a ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{a} \cdot \int_{0}^{1} \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= \frac{1}{a} [arctan (u)]_{0}^{1}

Compute the boundaries:

\frac{π}{4}

= \frac{1}{a} \cdot \frac{π}{4}

Simplify

= \frac{π}{4 a}

\int_{0}^{1} 5 x + 4 d x

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\int_{0}^{5} (2 x + 1) d x

\int_{0}^{2} (x^{2} - 9 x + 14) d x

What is the integral from 0 to a of 1/(a^2+x^2) ?
The integral from 0 to a of 1/(a^2+x^2) is pi/(4a)