What is the integral from 0 to 4 of (sqrt(x))^2 ?

The integral from 0 to 4 of (sqrt(x))^2 is 8

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integral from 0 to 4 of (sqrt(x))^2

\int_{0}^{4} (x)^{2} d x

8

Solution steps

\int_{0}^{4} (x)^{2} d x

Simplify

(x)^{2} : x

= \int_{0}^{4} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{4}

= [\frac{x ^{2}}{2}]_{0}^{4}

Compute the boundaries:

8

= 8

\int_{0}^{5} \frac{x}{49 + 3 x} d x

\int_{0}^{0.6} sin (x^{2}) d x

\int_{\frac{π}{6}}^{\frac{π}{3}} cos (x) d x

\int_{0}^{y} 8 x y d x

\int_{0}^{4} (x^{2}) d x

What is the integral from 0 to 4 of (sqrt(x))^2 ?
The integral from 0 to 4 of (sqrt(x))^2 is 8