What is the integral from 0 to 4 of (x^2) ?

The integral from 0 to 4 of (x^2) is 64/3

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integral from 0 to 4 of (x^2)

\int_{0}^{4} (x^{2}) d x

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

\int_{0}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{4}

= [\frac{x ^{3}}{3}]_{0}^{4}

Compute the boundaries:

\frac{64}{3}

= \frac{64}{3}

\int_{6}^{11} \frac{1}{x ^{2}} d x

\int_{0}^{13} ∣ 11 - x ∣ d x

\int_{0}^{1} x + y d x

\int_{\frac{1}{2}}^{1} \frac{1}{x ^{2}} - \frac{1}{x} d x

\int_{3}^{7} ∣ x - 4 ∣ d x

What is the integral from 0 to 4 of (x^2) ?
The integral from 0 to 4 of (x^2) is 64/3