What is the integral from-pi/3 to (3pi)/4 of sin(x) ?

The integral from-pi/3 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1/2

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integral from-pi/3 to (3pi)/4 of sin(x)

\int_{- \frac{π}{3}}^{\frac{3 π}{4}} sin (x) d x

\frac{1}{2} + \frac{1}{2}

Decimal

1.20710 \dots

Solution steps

\int_{- \frac{π}{3}}^{\frac{3 π}{4}} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= [- cos (x)]_{- \frac{π}{3}}^{\frac{3 π}{4}}

Compute the boundaries:

\frac{1}{2} + \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

\int_{0}^{3} (9 x - x^{3}) d x

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\int_{3}^{6} \frac{1}{6 x - x ^{2}} d x

\int_{1}^{2} x^{2} x^{3} + 1 d x

\int_{1}^{2} \frac{1}{1 - e ^{x}} d x

What is the integral from-pi/3 to (3pi)/4 of sin(x) ?
The integral from-pi/3 to (3pi)/4 of sin(x) is 1/(sqrt(2))+1/2