What is the integral from 0 to 3 of 200+10x+1/3 x^2 ?

The integral from 0 to 3 of 200+10x+1/3 x^2 is 648

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integral from 0 to 3 of 200+10x+1/3 x^2

\int_{0}^{3} 200 + 10 x + \frac{1}{3} x^{2} d x

648

Solution steps

\int_{0}^{3} 200 + 10 x + \frac{1}{3} x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} 200 d x + \int_{0}^{3} 10 x d x + \int_{0}^{3} \frac{1}{3} x^{2} d x

\int_{0}^{3} 200 d x = 600

\int_{0}^{3} 10 x d x = 45

\int_{0}^{3} \frac{1}{3} x^{2} d x = 3

= 600 + 45 + 3

Simplify

= 648

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What is the integral from 0 to 3 of 200+10x+1/3 x^2 ?
The integral from 0 to 3 of 200+10x+1/3 x^2 is 648