What is the integral from 0 to 2pi of-cos(x) ?

The integral from 0 to 2pi of-cos(x) is 0

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integral from 0 to 2pi of-cos(x)

\int_{0}^{2 π} - cos (x) d x

0

Solution steps

\int_{0}^{2 π} - cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{2 π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= - [sin (x)]_{0}^{2 π}

Compute the boundaries:

0

= - 0

Simplify

= 0

\int_{- 2}^{2} 2 x^{2} d x

\int_{0}^{17} ∣ 15 - x ∣ d x

\int_{- 3}^{1} 2 d x

\int_{0}^{\infty} e^{- a x^{2}} d x

\int_{0}^{3} 3^{2 x} d x

What is the integral from 0 to 2pi of-cos(x) ?
The integral from 0 to 2pi of-cos(x) is 0