What is the integral from 1 to 2 of (7x^6-3x^2+2x) ?

The integral from 1 to 2 of (7x^6-3x^2+2x) is 123

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (7x^6-3x^2+2x)

\int_{1}^{2} (7 x^{6} - 3 x^{2} + 2 x) d x

123

Solution steps

\int_{1}^{2} 7 x^{6} - 3 x^{2} + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 7 x^{6} d x - \int_{1}^{2} 3 x^{2} d x + \int_{1}^{2} 2 x d x

\int_{1}^{2} 7 x^{6} d x = 127

\int_{1}^{2} 3 x^{2} d x = 7

\int_{1}^{2} 2 x d x = 3

= 127 - 7 + 3

Simplify

= 123

\int_{- π}^{π} x sin (2 x) d x

\int_{1}^{4} 5 x^{2} d x

\int_{0}^{0.5} \frac{sin ( 3 x )}{x} d x

\int_{1}^{e} x e^{2 x^{2} - 1} d x

\int_{1}^{6} x^{2} - 2 x - 8 d x

What is the integral from 1 to 2 of (7x^6-3x^2+2x) ?
The integral from 1 to 2 of (7x^6-3x^2+2x) is 123