What is the integral from 0 to 0.5 of (sin(3x))/x ?

The integral from 0 to 0.5 of (sin(3x))/x is \Si(1.5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.5 of (sin(3x))/x

\int_{0}^{0.5} \frac{sin ( 3 x )}{x} d x

Si (1.5)

Solution steps

\int_{0}^{0.5} \frac{sin ( 3 x )}{x} d x

Apply u-substitution

: \int_{0}^{1.5} \frac{sin ( u )}{u} d u

= \int_{0}^{1.5} \frac{sin ( u )}{u} d u

Use the nonelementary integral:

\int \frac{sin ( x )}{x} d x = Si (x)

= [Si (u)]_{0}^{1.5}

Compute the boundaries:

Si (1.5)

= Si (1.5)

\int_{1}^{e} x e^{2 x^{2} - 1} d x

\int_{1}^{6} x^{2} - 2 x - 8 d x

\int_{1}^{4} x^{2} + 4 x + 5 d x

\int_{3}^{9} \frac{1}{x ^{2}} d x

\int_{0}^{1} x^{2} - 4 x + 3 d x

What is the integral from 0 to 0.5 of (sin(3x))/x ?
The integral from 0 to 0.5 of (sin(3x))/x is \Si(1.5)