What is the integral from-1 to 1 of (-x^2|x|) ?

The integral from-1 to 1 of (-x^2|x|) is -1/2

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integral from-1 to 1 of (-x^2|x|)

\int_{- 1}^{1} (- x^{2} ∣ x ∣) d x

- \frac{1}{2}

Decimal

- 0.5

Solution steps

\int_{- 1}^{1} - x^{2} ∣ x ∣ d x

Eliminate Absolutes

= \int_{- 1}^{0} - x^{2} (- x) d x + \int_{0}^{1} - x^{2} x d x

\int_{- 1}^{0} - x^{2} (- x) d x = - \frac{1}{4}

\int_{0}^{1} - x^{2} x d x = - \frac{1}{4}

= - \frac{1}{4} - \frac{1}{4}

Simplify

- \frac{1}{4} - \frac{1}{4} : - \frac{1}{2}

= - \frac{1}{2}

\int_{0}^{1} x^{2} \cdot e^{x} d x

\int_{0}^{\frac{π}{2}} - cos (x) d x

\int_{0}^{4} (x^{3} - x^{2} + 1) d x

\int_{- 5}^{4} - x^{2} - 3 x d x

\int_{1}^{2} (3 x^{2} - 2 x + 1) d x

What is the integral from-1 to 1 of (-x^2|x|) ?
The integral from-1 to 1 of (-x^2|x|) is -1/2