What is the integral from 0 to 1 of sqrt(1-x^2)x ?

The integral from 0 to 1 of sqrt(1-x^2)x is 1/3

Popular >

integral from 0 to 1 of sqrt(1-x^2)x

\int_{0}^{1} 1 - x^{2} x d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{0}^{1} 1 - x^{2} x d x

Apply u-substitution

: \int_{1}^{0} - u^{2} d u

= \int_{1}^{0} - u^{2} d u

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} - u^{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - (- \int_{0}^{1} u^{2} d u)

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{0}^{1}

= - (- [\frac{u ^{3}}{3}]_{0}^{1})

Simplify

= [\frac{u ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\int_{0}^{0.5} 3 x^{2} d x

\int_{- 1}^{1} x e^{- x} d x

\int_{1}^{7} (2 x + \frac{1}{x}) d x

\int_{0}^{2} (6 x^{2} y - 2 x) d y

\int_{0}^{\frac{π}{2}} sin (2 x) sin (x) d x

What is the integral from 0 to 1 of sqrt(1-x^2)x ?
The integral from 0 to 1 of sqrt(1-x^2)x is 1/3