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Popular >

integral from 0 to 4 of x^2-2x

Solution

\int_{0}^{4} x^{2} - 2 x d x

Solution

\frac{16}{3}

+1

Decimal

5.33333 \dots

Solution steps

\int_{0}^{4} x^{2} - 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x^{2} d x - \int_{0}^{4} 2 x d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 2 x d x = 16

= \frac{64}{3} - 16

Simplify

\frac{64}{3} - 16 : \frac{16}{3}

= \frac{16}{3}

Graph

Popular Examples

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\int_{0}^{0.8} e^{- x^{2}} d x

integral from-2 to-1 of x^2-1

\int_{- 2}^{- 1} x^{2} - 1 d x

integral from-1 to 4 of x^2-4x

\int_{- 1}^{4} x^{2} - 4 x d x

integral from 0 to 4 of 5(1-e^y)

\int_{0}^{4} 5 (1 - e^{y}) d y

integral from 0 to pi of (sin(x)-6)

\int_{0}^{π} (sin (x) - 6) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of x^2-2x ?
The integral from 0 to 4 of x^2-2x is 16/3