What is the integral from 0 to pi of 3cos(x) ?

The integral from 0 to pi of 3cos(x) is 0

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integral from 0 to pi of 3cos(x)

\int_{0}^{π} 3 cos (x) d x

0

Solution steps

\int_{0}^{π} 3 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{0}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 3 [sin (x)]_{0}^{π}

Compute the boundaries:

0

= 3 \cdot 0

Simplify

= 0

\int_{0}^{1} x^{2} - x + 1 d x

\int_{1}^{3} 3 - x d x

\int_{1}^{3} \frac{3}{x ( x + 1 )} d x

\int_{0}^{1} 3 y^{2} d y

\int_{0}^{1} \frac{1}{2 x - x ^{2}} d x

What is the integral from 0 to pi of 3cos(x) ?
The integral from 0 to pi of 3cos(x) is 0