What is the integral from 2 to 25 of sin(2x) ?

The integral from 2 to 25 of sin(2x) is 1/2 (-cos(50)+cos(4))

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integral from 2 to 25 of sin(2x)

\int_{2}^{25} sin (2 x) d x

\frac{1}{2} (- cos (50) + cos (4))

Decimal Notation

- 0.80930 \dots

Solution steps

\int_{2}^{25} sin (2 x) d x

Apply u-substitution

: \int_{4}^{50} sin (u) \frac{1}{2} d u

= \int_{4}^{50} sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{4}^{50} sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} [- cos (u)]_{4}^{50}

Compute the boundaries:

- cos (50) + cos (4)

= \frac{1}{2} (- cos (50) + cos (4))

\frac{\partial}{\partial x} (d x)

\int (6 x + 8) d x

\int \frac{1}{( 1 - x ^{2} )} d x

10 y^{^{''}} + 80 y^{^{'}} + 200 y = 0

f (x) = \frac{x}{x ^{2} + 2}

What is the integral from 2 to 25 of sin(2x) ?
The integral from 2 to 25 of sin(2x) is 1/2 (-cos(50)+cos(4))