What is the integral of 1/(sqrt((1-x^2))) ?

The integral of 1/(sqrt((1-x^2))) is arcsin(x)+C

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integral of 1/(sqrt((1-x^2)))

\int \frac{1}{( 1 - x ^{2} )} d x

arcsin (x) + C

Solution steps

\int \frac{1}{1 - x ^{2}} d x

Use the common integral:

\int \frac{1}{1 - x ^{2}} d x = arcsin (x)

= arcsin (x)

Add a constant to the solution

= arcsin (x) + C

10 y^{^{''}} + 80 y^{^{'}} + 200 y = 0

f (x) = \frac{x}{x ^{2} + 2}

\frac{d}{d r} (6 ((6 r - 1) \cdot k + r) - 1)

\frac{\partial}{\partial x} (ln (\frac{x}{x + y}))

n = 1 \sum \infty \frac{1}{( n + 2 ) ^{2}}

What is the integral of 1/(sqrt((1-x^2))) ?
The integral of 1/(sqrt((1-x^2))) is arcsin(x)+C