What is the integral from-1 to 1 of (2x^2-3) ?

The integral from-1 to 1 of (2x^2-3) is -14/3

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integral from-1 to 1 of (2x^2-3)

\int_{- 1}^{1} (2 x^{2} - 3) d x

- \frac{14}{3}

Decimal

- 4.66666 \dots

Solution steps

\int_{- 1}^{1} 2 x^{2} - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 2 x^{2} d x - \int_{- 1}^{1} 3 d x

\int_{- 1}^{1} 2 x^{2} d x = \frac{4}{3}

\int_{- 1}^{1} 3 d x = 6

= \frac{4}{3} - 6

Simplify

\frac{4}{3} - 6 : - \frac{14}{3}

= - \frac{14}{3}

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What is the integral from-1 to 1 of (2x^2-3) ?
The integral from-1 to 1 of (2x^2-3) is -14/3