What is the integral from-2 to 1 of x^4+x^3-2x^2+4 ?

The integral from-2 to 1 of x^4+x^3-2x^2+4 is 177/20

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integral from-2 to 1 of x^4+x^3-2x^2+4

\int_{- 2}^{1} x^{4} + x^{3} - 2 x^{2} + 4 d x

\frac{177}{20}

Decimal

8.85

Solution steps

\int_{- 2}^{1} x^{4} + x^{3} - 2 x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} x^{4} d x + \int_{- 2}^{1} x^{3} d x - \int_{- 2}^{1} 2 x^{2} d x + \int_{- 2}^{1} 4 d x

\int_{- 2}^{1} x^{4} d x = \frac{33}{5}

\int_{- 2}^{1} x^{3} d x = - \frac{15}{4}

\int_{- 2}^{1} 2 x^{2} d x = 6

\int_{- 2}^{1} 4 d x = 12

= \frac{33}{5} - \frac{15}{4} - 6 + 12

Simplify

\frac{33}{5} - \frac{15}{4} - 6 + 12 : \frac{177}{20}

= \frac{177}{20}

\int_{- 2}^{2} x x^{2} + 1 d x

\int_{- π}^{π} cos (m x) cos (n x) d x

\int_{0}^{t} t e^{t - t} d t

\int_{x}^{x^{2}} t^{4} d t

\int_{0.2}^{2.2} x e^{x} d x

What is the integral from-2 to 1 of x^4+x^3-2x^2+4 ?
The integral from-2 to 1 of x^4+x^3-2x^2+4 is 177/20