What is the integral from 1 to 6 of 1 ?

The integral from 1 to 6 of 1 is 5

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integral from 1 to 6 of 1

\int_{1}^{6} 1

5

Solution steps

\int_{1}^{6} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{1}^{6}

Simplify

= [x]_{1}^{6}

Compute the boundaries:

5

= 5

\int_{0}^{9} \frac{4}{( 3 + x ) ^{2}} d x

\int_{0}^{1} x^{12} + 1 2^{x} d x

\int_{\frac{1}{2}}^{2} (4 - \frac{4}{x ^{2}}) d x

\int_{3}^{4} \frac{1}{x ^{2} - 3 x + 2} d x

\int_{2}^{4} (2 x + 1) d x