What is the integral from 2 to 6 of 1/(x^2) ?

The integral from 2 to 6 of 1/(x^2) is 1/3

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integral from 2 to 6 of 1/(x^2)

\int_{2}^{6} \frac{1}{x ^{2}} d x

\frac{1}{3}

Decimal

0.33333 \dots

Solution steps

\int_{2}^{6} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{2}^{6}

= [- \frac{1}{x}]_{2}^{6}

Compute the boundaries:

\frac{1}{3}

= \frac{1}{3}

\int_{0}^{6} e^{\frac{x}{2}} d x

\int_{- \frac{π}{2}}^{π} 7 cos (x) d x

\int_{0}^{1} x \cdot sin (nπ x) d x

\int_{- 1}^{1} (- x^{2} + 1) d x

\int_{0}^{2} x^{3} - x^{2} - 2 x d x

What is the integral from 2 to 6 of 1/(x^2) ?
The integral from 2 to 6 of 1/(x^2) is 1/3