What is the integral from-pi/2 to pi of 7cos(x) ?

The integral from-pi/2 to pi of 7cos(x) is 7

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integral from-pi/2 to pi of 7cos(x)

\int_{- \frac{π}{2}}^{π} 7 cos (x) d x

7

Solution steps

\int_{- \frac{π}{2}}^{π} 7 cos (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 7 \cdot \int_{- \frac{π}{2}}^{π} cos (x) d x

Use the common integral:

\int cos (x) d x = sin (x)

= 7 [sin (x)]_{- \frac{π}{2}}^{π}

Compute the boundaries:

1

= 7 \cdot 1

Simplify

= 7

\int_{0}^{1} x \cdot sin (nπ x) d x

\int_{- 1}^{1} (- x^{2} + 1) d x

\int_{0}^{2} x^{3} - x^{2} - 2 x d x

\int_{0}^{1} y d y

\int_{1}^{5} - x^{2} + 6 x - 5 d x

What is the integral from-pi/2 to pi of 7cos(x) ?
The integral from-pi/2 to pi of 7cos(x) is 7