What is the integral from 1 to 2 of (e^{2ln(x)})/x ?

The integral from 1 to 2 of (e^{2ln(x)})/x is 3/2

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integral from 1 to 2 of (e^{2ln(x)})/x

\int_{1}^{2} \frac{e ^{2 l n (x)}}{x} d x

\frac{3}{2}

Solution steps

\int_{1}^{2} \frac{e ^{2 l n (x)}}{x} d x

Simplify

\frac{e ^{2 l n (x)}}{x} : x

= \int_{1}^{2} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{1}^{2}

= [\frac{x ^{2}}{2}]_{1}^{2}

Compute the boundaries:

\frac{3}{2}

= \frac{3}{2}

\int_{- 1}^{1} (x + 1) 1 - x^{2} d x

\int_{1}^{8} x^{2} - 4 x - 12 d x

\int_{2}^{4} x^{2} - 4 d x

\int_{0}^{5} (x^{2} - 4) d x

\int_{0}^{θ} \frac{2 x}{θ ^{2}} d x

What is the integral from 1 to 2 of (e^{2ln(x)})/x ?
The integral from 1 to 2 of (e^{2ln(x)})/x is 3/2