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Popular >

integral from 0 to 5 of (x^2-4)

Solution

\int_{0}^{5} (x^{2} - 4) d x

Solution

\frac{65}{3}

+1

Solution steps

\int_{0}^{5} x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5} x^{2} d x - \int_{0}^{5} 4 d x

\int_{0}^{5} x^{2} d x = \frac{125}{3}

\int_{0}^{5} 4 d x = 20

= \frac{125}{3} - 20

Simplify

\frac{125}{3} - 20 : \frac{65}{3}

= \frac{65}{3}

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\int_{0}^{b} e^{- x} d x

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\int_{- 2}^{1} x^{2} + 2 x + 1 d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 5 of (x^2-4) ?
The integral from 0 to 5 of (x^2-4) is 65/3