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Popular >

integral from-1 to 5 of (3x^4+2x^2+3)

Solution

\int_{- 1}^{5} (3 x^{4} + 2 x^{2} + 3) d x

Solution

\frac{9888}{5}

+1

Solution steps

\int_{- 1}^{5} 3 x^{4} + 2 x^{2} + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{5} 3 x^{4} d x + \int_{- 1}^{5} 2 x^{2} d x + \int_{- 1}^{5} 3 d x

\int_{- 1}^{5} 3 x^{4} d x = \frac{9378}{5}

\int_{- 1}^{5} 2 x^{2} d x = 84

\int_{- 1}^{5} 3 d x = 18

= \frac{9378}{5} + 84 + 18

Simplify

\frac{9378}{5} + 84 + 18 : \frac{9888}{5}

= \frac{9888}{5}

Popular Examples

integral from pi to 2pi of sin(x)sin(nx)

\int_{π}^{2 π} sin (x) sin (n x) d x

integral from 0 to 5 of-3x

\int_{0}^{5} - 3 x d x

integral from 0 to 8 of |x-4|

\int_{0}^{8} ∣ x - 4 ∣ d x

integral from-2 to 5 of 1

\int_{- 2}^{5} 1 d x

integral from 1 to 2 of (2x+3)

\int_{1}^{2} (2 x + 3) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 5 of (3x^4+2x^2+3) ?
The integral from-1 to 5 of (3x^4+2x^2+3) is 9888/5