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Popular >

integral from 1 to 2 of (2x+3)

Solution

\int_{1}^{2} (2 x + 3) d x

Solution

6

Solution steps

\int_{1}^{2} 2 x + 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 2 x d x + \int_{1}^{2} 3 d x

\int_{1}^{2} 2 x d x = 3

\int_{1}^{2} 3 d x = 3

= 3 + 3

Simplify

= 6

Popular Examples

integral from 0 to 3 of x^2-1

\int_{0}^{3} x^{2} - 1 d x

integral from 4 to 7 of x^3

\int_{4}^{7} x^{3} d x

integral from 0 to 1 of x^3-3x^2

\int_{0}^{1} x^{3} - 3 x^{2} d x

integral from 0 to 1 of (3x^2-x+1)

\int_{0}^{1} (3 x^{2} - x + 1) d x

integral from 2 to 5 of 2000x+1000

\int_{2}^{5} 2000 x + 1000 d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (2x+3) ?
The integral from 1 to 2 of (2x+3) is 6