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Popular >

integral from 0 to 4 of 16x-x^3

Solution

\int_{0}^{4} 16 x - x^{3} d x

Solution

64

Solution steps

\int_{0}^{4} 16 x - x^{3} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 16 x d x - \int_{0}^{4} x^{3} d x

\int_{0}^{4} 16 x d x = 128

\int_{0}^{4} x^{3} d x = 64

= 128 - 64

Simplify

= 64

Popular Examples

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\int_{0}^{6} ∣ x - 5 ∣ d x

integral from-1 to 2 of (2x+5)

\int_{- 1}^{2} (2 x + 5) d x

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\int_{0}^{l n (5)} 2 e^{2 x} d x

integral from 0 to 2pi of (cos(x))^4

\int_{0}^{2 π} (cos (x))^{4} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 16x-x^3 ?
The integral from 0 to 4 of 16x-x^3 is 64