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Popular >

integral from 0 to 2 of (3x+1)

Solution

\int_{0}^{2} (3 x + 1) d x

Solution

8

Solution steps

\int_{0}^{2} 3 x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 3 x d x + \int_{0}^{2} 1 d x

\int_{0}^{2} 3 x d x = 6

\int_{0}^{2} 1 d x = 2

= 6 + 2

Simplify

= 8

Popular Examples

integral from 8 to 9 of 1

\int_{8}^{9} 1 d t

integral from 2 to 4 of x/((x^2+5)^3)

\int_{2}^{4} \frac{x}{( x ^{2} + 5 ) ^{3}} d x

integral from 3 to 4 of x^2+x-5

\int_{3}^{4} x^{2} + x - 5 d x

integral from 0 to r of r

\int_{0}^{r} r d r

integral from-x to x of x

\int_{- x}^{x} x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of (3x+1) ?
The integral from 0 to 2 of (3x+1) is 8