What is the integral from 1 to 2 of 2^x ?

The integral from 1 to 2 of 2^x is 2/(ln(2))

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integral from 1 to 2 of 2^x

\int_{1}^{2} 2^{x} d x

\frac{2}{ln ( 2 )}

Decimal Notation

2.88539 \dots

Solution steps

\int_{1}^{2} 2^{x} d x

\int a^{x} d x = \frac{a ^{x}}{ln a}

= [\frac{2 ^{x}}{ln ( 2 )}]_{1}^{2}

Compute the boundaries:

\frac{2}{ln ( 2 )}

= \frac{2}{ln ( 2 )}

\int_{1}^{4} 2 x - x^{2} d x

\int_{0}^{2} \frac{t}{5 + t ^{2}} d t

\int_{0}^{\frac{π}{4}} sin (2 x + \frac{π}{2}) d x

\int_{0}^{\frac{π}{2}} x^{2} \cdot cos (x) d x

What is the integral from 1 to 2 of 2^x ?
The integral from 1 to 2 of 2^x is 2/(ln(2))