What is the integral from 1 to 5 of (6x^2+7x) ?

The integral from 1 to 5 of (6x^2+7x) is 332

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integral from 1 to 5 of (6x^2+7x)

\int_{1}^{5} (6 x^{2} + 7 x) d x

332

Solution steps

\int_{1}^{5} 6 x^{2} + 7 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} 6 x^{2} d x + \int_{1}^{5} 7 x d x

\int_{1}^{5} 6 x^{2} d x = 248

\int_{1}^{5} 7 x d x = 84

= 248 + 84

Simplify

= 332

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What is the integral from 1 to 5 of (6x^2+7x) ?
The integral from 1 to 5 of (6x^2+7x) is 332