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Popular >

integral from 1 to 2 of (x+2)

Solution

\int_{1}^{2} (x + 2) d x

Solution

\frac{7}{2}

+1

Solution steps

\int_{1}^{2} x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x d x + \int_{1}^{2} 2 d x

\int_{1}^{2} x d x = \frac{3}{2}

\int_{1}^{2} 2 d x = 2

= \frac{3}{2} + 2

Simplify

\frac{3}{2} + 2 : \frac{7}{2}

= \frac{7}{2}

Popular Examples

integral from 0 to 3 of |3x-8|

\int_{0}^{3} ∣ 3 x - 8 ∣ d x

integral from 2x to x^2 of cos(t)sin(t)

\int_{2 x}^{x^{2}} cos (t) sin (t) d t

integral from 0 to 1-x of ((1-x-y)^2)/2

\int_{0}^{1 - x} \frac{( 1 - x - y ) ^{2}}{2} d y

integral from 0 to 2 of x^2+x+1

\int_{0}^{2} x^{2} + x + 1 d x

integral from 2 to 3 of 1/(xln(x))

\int_{2}^{3} \frac{1}{x ln ( x )} d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (x+2) ?
The integral from 1 to 2 of (x+2) is 7/2