What is the integral from-1 to 4 of x^2 ?

The integral from-1 to 4 of x^2 is 65/3

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integral from-1 to 4 of x^2

\int_{- 1}^{4} x^{2} d x

\frac{65}{3}

Decimal Notation

21.66666 \dots

Solution steps

\int_{- 1}^{4} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{4}

= [\frac{x ^{3}}{3}]_{- 1}^{4}

Compute the boundaries:

\frac{65}{3}

= \frac{65}{3}

\int_{0}^{3} (2 - x) d x

\int_{- 2}^{2} x^{3} + x d x

\int_{1}^{3} 3 x (x^{2} + 5) d x

\int_{0}^{1} (x^{2})^{2} d x

\int_{0}^{1} 2 x + 3 d x

What is the integral from-1 to 4 of x^2 ?
The integral from-1 to 4 of x^2 is 65/3