What is the integral from-2 to 2 of (x^2) ?

The integral from-2 to 2 of (x^2) is 16/3

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integral from-2 to 2 of (x^2)

\int_{- 2}^{2} (x^{2}) d x

\frac{16}{3}

Solution steps

\int_{- 2}^{2} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 2}^{2}

= [\frac{x ^{3}}{3}]_{- 2}^{2}

Compute the boundaries:

\frac{16}{3}

= \frac{16}{3}

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What is the integral from-2 to 2 of (x^2) ?
The integral from-2 to 2 of (x^2) is 16/3