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Popular >

integral from 0 to 1 of e^x-e

Solution

\int_{0}^{1} e^{x} - e d x

Solution

- 1

Solution steps

\int_{0}^{1} e^{x} - e d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} e^{x} d x - \int_{0}^{1} e d x

\int_{0}^{1} e^{x} d x = e - 1

\int_{0}^{1} e d x = e

= e - 1 - e

Simplify

= - 1

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\int_{1}^{8} 1 + \frac{81}{16} x d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of e^x-e ?
The integral from 0 to 1 of e^x-e is -1