What is the integral from 6 to 11 of (4-10e^{-0.2x}) ?

The integral from 6 to 11 of (4-10e^{-0.2x}) is 10.48044…

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integral from 6 to 11 of (4-10e^{-0.2x})

\int_{6}^{11} (4 - 10 e^{- 0.2 x}) d x

10.48044 \dots

Solution steps

\int_{6}^{11} 4 - 10 e^{- 0.2 x} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{6}^{11} 4 d x - \int_{6}^{11} 10 e^{- 0.2 x} d x

\int_{6}^{11} 4 d x = 20

\int_{6}^{11} 10 e^{- 0.2 x} d x = 9.51955 \dots

= 20 - 9.51955 \dots

Simplify

= 10.48044 \dots

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What is the integral from 6 to 11 of (4-10e^{-0.2x}) ?
The integral from 6 to 11 of (4-10e^{-0.2x}) is 10.48044…