What is the integral from 0 to 4 of sqrt(3x+4) ?

The integral from 0 to 4 of sqrt(3x+4) is 112/9

Popular >

integral from 0 to 4 of sqrt(3x+4)

\int_{0}^{4} 3 x + 4 d x

\frac{112}{9}

Decimal Notation

12.44444 \dots

Solution steps

\int_{0}^{4} 3 x + 4 d x

Apply u-substitution

: \int_{4}^{16} \frac{u}{3} d u

= \int_{4}^{16} \frac{u}{3} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{4}^{16} u d u

Apply the Power Rule

: [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{16}

= \frac{1}{3} [\frac{2}{3} u^{\frac{3}{2}}]_{4}^{16}

Compute the boundaries:

\frac{112}{3}

= \frac{1}{3} \cdot \frac{112}{3}

Simplify

= \frac{112}{9}

\int_{0}^{1} t^{7} (1 + t^{8})^{7} d t

\int_{1}^{3} x^{2} + 3 x d x

\int_{0}^{s i n (x)} t d t

\int_{- \frac{π}{4}}^{\frac{π}{4}} (- cos (x)) d x

\int_{1}^{5} \frac{1}{x ^{3}} d x

What is the integral from 0 to 4 of sqrt(3x+4) ?
The integral from 0 to 4 of sqrt(3x+4) is 112/9