What is the integral from-1 to 1 of kx^2 ?

The integral from-1 to 1 of kx^2 is (2k)/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-1 to 1 of kx^2

\int_{- 1}^{1} k x^{2} d x

\frac{2 k}{3}

Solution steps

\int_{- 1}^{1} k x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= k \cdot \int_{- 1}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{- 1}^{1}

= k [\frac{x ^{3}}{3}]_{- 1}^{1}

Compute the boundaries:

\frac{2}{3}

= k \frac{2}{3}

Simplify

= \frac{2 k}{3}

\int_{0}^{1} x x^{2} + 3 d x

\int_{- 1}^{1} t^{3} d t

\int_{4}^{8} x d x

\int_{0}^{π + 2 i} cos (\frac{z}{2}) d z

\int_{0}^{a} \frac{1}{x} d x

What is the integral from-1 to 1 of kx^2 ?
The integral from-1 to 1 of kx^2 is (2k)/3