What is the integral from-1 to 1 of (3x^2-1)/(x^2) ?

The integral from-1 to 1 of (3x^2-1)/(x^2) is diverges

Popular >

integral from-1 to 1 of (3x^2-1)/(x^2)

\int_{- 1}^{1} \frac{3 x ^{2} - 1}{x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{1} \frac{3 x ^{2} - 1}{x ^{2}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 1}^{0} \frac{3 x ^{2} - 1}{x ^{2}} d x + \int_{0}^{1} \frac{3 x ^{2} - 1}{x ^{2}} d x

\int_{- 1}^{0} \frac{3 x ^{2} - 1}{x ^{2}} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

\int_{0}^{1} e^{x} cos (e^{x}) d x

\int_{6}^{8} \frac{1}{x ^{2}} d x

\int_{\frac{π}{4}}^{π} cos (x) d x

\int_{1}^{e} \frac{( 2 + ln ( x ) ) ^{2}}{x} d x

\int_{99}^{100} (x^{2} + 1) d x

What is the integral from-1 to 1 of (3x^2-1)/(x^2) ?
The integral from-1 to 1 of (3x^2-1)/(x^2) is diverges