What is the integral from 0 to 1 of x^{8/9} ?

The integral from 0 to 1 of x^{8/9} is 9/17

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integral from 0 to 1 of x^{8/9}

\int_{0}^{1} x^{\frac{8}{9}} d x

\frac{9}{17}

Decimal Notation

0.52941 \dots

Solution steps

\int_{0}^{1} x^{\frac{8}{9}} d x

Apply the Power Rule

: [\frac{9}{17} x^{\frac{17}{9}}]_{0}^{1}

= [\frac{9}{17} x^{\frac{17}{9}}]_{0}^{1}

Compute the boundaries:

\frac{9}{17}

= \frac{9}{17}

\int_{1}^{5} (x + 1) d x

\int_{0}^{\frac{π}{2}} x - sin (x) d x

\int_{- 1}^{2} \frac{x}{x + 2} d x

\int_{0}^{\frac{x}{2}} sin (2 t) d t

\int_{1}^{5} x x - 1 d x

What is the integral from 0 to 1 of x^{8/9} ?
The integral from 0 to 1 of x^{8/9} is 9/17