What is the integral from-2 to x of (26t^2-25t) ?

The integral from-2 to x of (26t^2-25t) is (26(x^3+8))/3-25((x^2)/2-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from-2 to x of (26t^2-25t)

\int_{- 2}^{x} (26 t^{2} - 25 t) d t

\frac{26 ( x ^{3} + 8 )}{3} - 25 (\frac{x ^{2}}{2} - 2)

Solution steps

\int_{- 2}^{x} 26 t^{2} - 25 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{x} 26 t^{2} d t - \int_{- 2}^{x} 25 t d t

\int_{- 2}^{x} 26 t^{2} d t = \frac{26 ( x ^{3} + 8 )}{3}

\int_{- 2}^{x} 25 t d t = 25 (\frac{x ^{2}}{2} - 2)

= \frac{26 ( x ^{3} + 8 )}{3} - 25 (\frac{x ^{2}}{2} - 2)

\int_{0}^{t} e^{- 2 t} d t

\int_{- 1}^{0} x e^{- x} d x

\int_{e}^{e^{3}} \frac{ln ( x )}{x} d x

\int_{2}^{2} 1

\int_{x^{2}}^{x} \frac{x}{y} d y

What is the integral from-2 to x of (26t^2-25t) ?
The integral from-2 to x of (26t^2-25t) is (26(x^3+8))/3-25((x^2)/2-2)