What is the integral from 1 to 3 of (1/x)^2 ?

The integral from 1 to 3 of (1/x)^2 is 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of (1/x)^2

\int_{1}^{3} (\frac{1}{x})^{2} d x

\frac{2}{3}

Decimal Notation

0.66666 \dots

Solution steps

\int_{1}^{3} (\frac{1}{x})^{2} d x

Simplify

(\frac{1}{x})^{2} : \frac{1}{x ^{2}}

= \int_{1}^{3} \frac{1}{x ^{2}} d x

Apply the Power Rule

: [- \frac{1}{x}]_{1}^{3}

= [- \frac{1}{x}]_{1}^{3}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

\int_{- 1}^{1} (2 x + 1) d x

\int_{1}^{6} 2 x d x

\int_{2}^{6} x^{2} - 7 x + 6 d x

\int_{5}^{8} 10 lo g_{4} (t) d t

\int_{- 3}^{2} 1 d x

What is the integral from 1 to 3 of (1/x)^2 ?
The integral from 1 to 3 of (1/x)^2 is 2/3