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Popular >

integral from 0 to 1 of x+1/2

Solution

\int_{0}^{1} x + \frac{1}{2} d x

Solution

1

Solution steps

\int_{0}^{1} x + \frac{1}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x d x + \int_{0}^{1} \frac{1}{2} d x

\int_{0}^{1} x d x = \frac{1}{2}

\int_{0}^{1} \frac{1}{2} d x = \frac{1}{2}

= \frac{1}{2} + \frac{1}{2}

Simplify

\frac{1}{2} + \frac{1}{2} : 1

= 1

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\int_{- 1}^{0} x^{5} x^{3} + 1 d x

integral from-1 to 1 of 1/(1-x^2)

\int_{- 1}^{1} \frac{1}{1 - x ^{2}} d x

integral from 50 to 100 of x/(15+4x^2)

\int_{50}^{100} \frac{x}{15 + 4 x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of x+1/2 ?
The integral from 0 to 1 of x+1/2 is 1